{Assume the logathmic scale from 10 to 1000.
 
We are in the middle, i.e. "linear" 505.}

//See the code

aProportion := (505-10)/(1000-10) = 495/990 = 0.5

AMin := logn(10, 10) = 1
 
AMax := logn(10, 1000) = 3

Result := 10^(1+(3+1)*0.5) = 10^2 = 100
 
{... which is correct since 100 is in the middle of logarithmic scale 10 .. 1000.}

 |         |        |       |     |   |  | |||         |        |       |     |   |  | ||         
10                                          100 (505)                                  1000